做网站空间百度云和阿里云区别宁德市高中阶段招生信息平台
文章目录
- 题目描述
- 题解思路
- 题解代码
- 题目链接
题目描述
题解思路
我们只需要遍历长度长度为k的窗口，然后把窗口内数字之和填充到结果数组中的对应位置即可
题解代码
impl Solution {pub fn decrypt(code: Vec<i32>, k: i32) -> Vec<i32> {let n = code.len();let mut ans = vec![0i32; n];if k == 0 {return ans;}let mut sum = 0;if k > 0 {for i in 1..=k as usize {sum += code[i];}ans[0] = sum;for i in 1..n {sum += code[(i + k as usize) % n] - code[i];ans[i] = sum;} } else {for i in k..0 {sum += code[n + i as usize];}ans[0] = sum;for i in 1..n {sum += code[i - 1] - code[(i + k as usize - 1 + n) % n];ans[i] = sum;}}ans}
}
题目链接
https://leetcode.cn/problems/defuse-the-bomb/